What does the concentration-time graph look like for first-order versus zero-order elimination?

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Multiple Choice

What does the concentration-time graph look like for first-order versus zero-order elimination?

Explanation:
How the concentration of a drug falls over time depends on the order of elimination. In first-order elimination, the removal rate is proportional to how much drug is present, so the concentration-time profile follows an exponential decay: C = C0 e^{-kt}. This means the curve is curved—steepest at the start and then it gradually levels off as time goes on. In zero-order elimination, the drug is removed at a constant amount per unit time, so the concentration declines linearly: C = C0 − k0 t. On a concentration-versus-time graph, this is a straight line with a constant negative slope, at least until the drug concentration hits zero or the elimination mechanism changes. Therefore, the correct description is that first-order elimination shows an exponential decline, while zero-order elimination shows a straight-line decline.

How the concentration of a drug falls over time depends on the order of elimination. In first-order elimination, the removal rate is proportional to how much drug is present, so the concentration-time profile follows an exponential decay: C = C0 e^{-kt}. This means the curve is curved—steepest at the start and then it gradually levels off as time goes on.

In zero-order elimination, the drug is removed at a constant amount per unit time, so the concentration declines linearly: C = C0 − k0 t. On a concentration-versus-time graph, this is a straight line with a constant negative slope, at least until the drug concentration hits zero or the elimination mechanism changes.

Therefore, the correct description is that first-order elimination shows an exponential decline, while zero-order elimination shows a straight-line decline.

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